Base | Representation |
---|---|
bin | 110001011001011100… |
… | …001000001111000111 |
3 | 12001220110101222021020 |
4 | 301121130020033013 |
5 | 1332111234403133 |
6 | 40211042322223 |
7 | 3555245603106 |
oct | 613134101707 |
9 | 161813358236 |
10 | 53040153543 |
11 | 20548869443 |
12 | a343059373 |
13 | 5003872950 |
14 | 27d23ca03d |
15 | 15a671b0b3 |
hex | c597083c7 |
53040153543 has 32 divisors (see below), whose sum is σ = 76522649280. Its totient is φ = 32485155840.
The previous prime is 53040153533. The next prime is 53040153557. The reversal of 53040153543 is 34535104035.
It is not a de Polignac number, because 53040153543 - 25 = 53040153511 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (53040153503) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 7349805 + ... + 7357017.
It is an arithmetic number, because the mean of its divisors is an integer number (2391332790).
Almost surely, 253040153543 is an apocalyptic number.
53040153543 is a deficient number, since it is larger than the sum of its proper divisors (23482495737).
53040153543 is a wasteful number, since it uses less digits than its factorization.
53040153543 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 8099.
The product of its (nonzero) digits is 54000, while the sum is 33.
Adding to 53040153543 its reverse (34535104035), we get a palindrome (87575257578).
The spelling of 53040153543 in words is "fifty-three billion, forty million, one hundred fifty-three thousand, five hundred forty-three".
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