Base | Representation |
---|---|
bin | 100110100110011001111… |
… | …0010111110100101110111 |
3 | 200210011112021110202222102 |
4 | 1031030303302332211313 |
5 | 1143404423311042101 |
6 | 15141053125252315 |
7 | 1055166436445021 |
oct | 115146362764567 |
9 | 20704467422872 |
10 | 5305153612151 |
11 | 17659a29aa958 |
12 | 71821126409b |
13 | 2c6373816803 |
14 | 144ab1135011 |
15 | 92eec57b86b |
hex | 4d333cbe977 |
5305153612151 has 2 divisors, whose sum is σ = 5305153612152. Its totient is φ = 5305153612150.
The previous prime is 5305153612141. The next prime is 5305153612153. The reversal of 5305153612151 is 1512163515035.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5305153612151 is a prime.
Together with 5305153612153, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5305153612153) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2652576806075 + 2652576806076.
It is an arithmetic number, because the mean of its divisors is an integer number (2652576806076).
Almost surely, 25305153612151 is an apocalyptic number.
5305153612151 is a deficient number, since it is larger than the sum of its proper divisors (1).
5305153612151 is an equidigital number, since it uses as much as digits as its factorization.
5305153612151 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 67500, while the sum is 38.
The spelling of 5305153612151 in words is "five trillion, three hundred five billion, one hundred fifty-three million, six hundred twelve thousand, one hundred fifty-one".
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