Base | Representation |
---|---|
bin | 11000001000000001101010… |
… | …11110011110110010000000 |
3 | 20221211202100022121201111222 |
4 | 30010000311132132302000 |
5 | 23423202134301114130 |
6 | 304455523323254212 |
7 | 14113622162633414 |
oct | 1404006536366200 |
9 | 227752308551458 |
10 | 53052333223040 |
11 | 159a440603a918 |
12 | 5b49a9307a368 |
13 | 237aa764caa38 |
14 | d15a64a6ad44 |
15 | 62002d9cdce5 |
hex | 30403579ec80 |
53052333223040 has 64 divisors (see below), whose sum is σ = 130919467518720. Its totient is φ = 20536387046400.
The previous prime is 53052333223033. The next prime is 53052333223051. The reversal of 53052333223040 is 4032233325035.
It is a tau number, because it is divible by the number of its divisors (64).
It is a super-3 number, since 3×530523332230403 (a number of 42 digits) contains 333 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1336984526 + ... + 1337024205.
It is an arithmetic number, because the mean of its divisors is an integer number (2045616679980).
Almost surely, 253052333223040 is an apocalyptic number.
It is an amenable number.
53052333223040 is an abundant number, since it is smaller than the sum of its proper divisors (77867134295680).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
53052333223040 is a wasteful number, since it uses less digits than its factorization.
53052333223040 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2674008781 (or 2674008769 counting only the distinct ones).
The product of its (nonzero) digits is 194400, while the sum is 35.
Adding to 53052333223040 its reverse (4032233325035), we get a palindrome (57084566548075).
The spelling of 53052333223040 in words is "fifty-three trillion, fifty-two billion, three hundred thirty-three million, two hundred twenty-three thousand, forty".
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