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53054113241021 is a prime number
BaseRepresentation
bin11000001000000100111111…
…00100101101011110111101
320221211220221101001000010212
430010002133210231132331
523423214310442203041
6304500420111242205
714114014245555254
oct1404023744553675
9227756841030125
1053054113241021
11159a5139896762
125b4a2ab219365
13237ac9b212909
14d15b9322179b
156200d4ddb8eb
hex30409f92d7bd

53054113241021 has 2 divisors, whose sum is σ = 53054113241022. Its totient is φ = 53054113241020.

The previous prime is 53054113241009. The next prime is 53054113241023. The reversal of 53054113241021 is 12014231145035.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 39054437916025 + 13999675324996 = 6249355^2 + 3741614^2 .

It is a cyclic number.

It is not a de Polignac number, because 53054113241021 - 222 = 53054109046717 is a prime.

Together with 53054113241023, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (53054113241023) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26527056620510 + 26527056620511.

It is an arithmetic number, because the mean of its divisors is an integer number (26527056620511).

Almost surely, 253054113241021 is an apocalyptic number.

It is an amenable number.

53054113241021 is a deficient number, since it is larger than the sum of its proper divisors (1).

53054113241021 is an equidigital number, since it uses as much as digits as its factorization.

53054113241021 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 14400, while the sum is 32.

Adding to 53054113241021 its reverse (12014231145035), we get a palindrome (65068344386056).

The spelling of 53054113241021 in words is "fifty-three trillion, fifty-four billion, one hundred thirteen million, two hundred forty-one thousand, twenty-one".