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5310143340343 is a prime number
BaseRepresentation
bin100110101000101110100…
…1101010001111100110111
3200210122102000112020021021
41031101131031101330313
51144000133143342333
615143240212402011
71055434205441362
oct115213515217467
920718360466237
105310143340343
111768023531566
12719184316307
132c698a4b9bba
14145025ac10d9
15931e065482d
hex4d45d351f37

5310143340343 has 2 divisors, whose sum is σ = 5310143340344. Its totient is φ = 5310143340342.

The previous prime is 5310143340331. The next prime is 5310143340377. The reversal of 5310143340343 is 3430433410135.

It is an a-pointer prime, because the next prime (5310143340377) can be obtained adding 5310143340343 to its sum of digits (34).

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 5310143340343 - 221 = 5310141243191 is a prime.

It is a super-2 number, since 2×53101433403432 (a number of 26 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 5310143340299 and 5310143340308.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5310143340743) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2655071670171 + 2655071670172.

It is an arithmetic number, because the mean of its divisors is an integer number (2655071670172).

Almost surely, 25310143340343 is an apocalyptic number.

5310143340343 is a deficient number, since it is larger than the sum of its proper divisors (1).

5310143340343 is an equidigital number, since it uses as much as digits as its factorization.

5310143340343 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 77760, while the sum is 34.

Adding to 5310143340343 its reverse (3430433410135), we get a palindrome (8740576750478).

The spelling of 5310143340343 in words is "five trillion, three hundred ten billion, one hundred forty-three million, three hundred forty thousand, three hundred forty-three".