Base | Representation |
---|---|
bin | 111100010111101100110111… |
… | …1110100000001011010100110 |
3 | 2120122012022021212010121221212 |
4 | 1320233121233310001122212 |
5 | 1024100240142331413420 |
6 | 5121220341251111422 |
7 | 216565102011036656 |
oct | 17057315764013246 |
9 | 2518168255117855 |
10 | 531023042451110 |
11 | 1442226757a3340 |
12 | 4b6839a65a2572 |
13 | 19a3c347ba2011 |
14 | 951b91c22c366 |
15 | 415d1dbd363c5 |
hex | 1e2f66fd016a6 |
531023042451110 has 32 divisors (see below), whose sum is σ = 1042749968320512. Its totient is φ = 193096730342880.
The previous prime is 531023042451089. The next prime is 531023042451113. The reversal of 531023042451110 is 11154240320135.
It is a super-2 number, since 2×5310230424511102 (a number of 30 digits) contains 22 as substring.
It is a Curzon number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (531023042451113) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 23620844 + ... + 40249103.
It is an arithmetic number, because the mean of its divisors is an integer number (32585936510016).
Almost surely, 2531023042451110 is an apocalyptic number.
531023042451110 is a deficient number, since it is larger than the sum of its proper divisors (511726925869402).
531023042451110 is a wasteful number, since it uses less digits than its factorization.
531023042451110 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 63945548.
The product of its (nonzero) digits is 14400, while the sum is 32.
Adding to 531023042451110 its reverse (11154240320135), we get a palindrome (542177282771245).
The spelling of 531023042451110 in words is "five hundred thirty-one trillion, twenty-three billion, forty-two million, four hundred fifty-one thousand, one hundred ten".
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