Base | Representation |
---|---|
bin | 100110101000110110010… |
… | …0110000101010011110000 |
3 | 200210200002000022010021212 |
4 | 1031101230212011103300 |
5 | 1144001200241003100 |
6 | 15143321553535252 |
7 | 1055443461660533 |
oct | 115215446052360 |
9 | 20720060263255 |
10 | 5310401500400 |
11 | 1768146228a87 |
12 | 719236874528 |
13 | 2c69cbb28829 |
14 | 14504c0c2a1a |
15 | 9320814b635 |
hex | 4d46c9854f0 |
5310401500400 has 30 divisors (see below), whose sum is σ = 12758239605672. Its totient is φ = 2124160600000.
The previous prime is 5310401500343. The next prime is 5310401500493. The reversal of 5310401500400 is 40051040135.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 6638001476 + ... + 6638002275.
Almost surely, 25310401500400 is an apocalyptic number.
5310401500400 is a gapful number since it is divisible by the number (50) formed by its first and last digit.
It is an amenable number.
5310401500400 is an abundant number, since it is smaller than the sum of its proper divisors (7447838105272).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
5310401500400 is a wasteful number, since it uses less digits than its factorization.
5310401500400 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 13276003769 (or 13276003758 counting only the distinct ones).
The product of its (nonzero) digits is 1200, while the sum is 23.
Adding to 5310401500400 its reverse (40051040135), we get a palindrome (5350452540535).
The spelling of 5310401500400 in words is "five trillion, three hundred ten billion, four hundred one million, five hundred thousand, four hundred".
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