Base | Representation |
---|---|
bin | 110001011101101010… |
… | …011011010000001000 |
3 | 12002002101201212111000 |
4 | 301131222123100020 |
5 | 1332232404312222 |
6 | 40222053135000 |
7 | 3560066065443 |
oct | 613552332010 |
9 | 162071655430 |
10 | 53111010312 |
11 | 20584865158 |
12 | a36292a460 |
13 | 5015451429 |
14 | 27db99265a |
15 | 15aca659ac |
hex | c5da9b408 |
53111010312 has 64 divisors (see below), whose sum is σ = 150669561600. Its totient is φ = 17326992960.
The previous prime is 53111010283. The next prime is 53111010313. The reversal of 53111010312 is 21301011135.
53111010312 is a `hidden beast` number, since 531 + 1 + 101 + 0 + 31 + 2 = 666.
It is a super-3 number, since 3×531110103123 (a number of 33 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a Harshad number since it is a multiple of its sum of digits (18).
It is not an unprimeable number, because it can be changed into a prime (53111010313) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2605639 + ... + 2625942.
It is an arithmetic number, because the mean of its divisors is an integer number (2354211900).
Almost surely, 253111010312 is an apocalyptic number.
It is an amenable number.
53111010312 is an abundant number, since it is smaller than the sum of its proper divisors (97558551288).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
53111010312 is a wasteful number, since it uses less digits than its factorization.
53111010312 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5231643 (or 5231633 counting only the distinct ones).
The product of its (nonzero) digits is 90, while the sum is 18.
Adding to 53111010312 its reverse (21301011135), we get a palindrome (74412021447).
The spelling of 53111010312 in words is "fifty-three billion, one hundred eleven million, ten thousand, three hundred twelve".
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