Base | Representation |
---|---|
bin | 110001011101111010… |
… | …011010111000011100 |
3 | 12002002200121212220110 |
4 | 301131322122320130 |
5 | 1332234442444400 |
6 | 40222323050020 |
7 | 3560146530351 |
oct | 613572327034 |
9 | 162080555813 |
10 | 53115203100 |
11 | 20587169273 |
12 | a364210910 |
13 | 501628b97b |
14 | 27dc364628 |
15 | 15ad0e2e50 |
hex | c5de9ae1c |
53115203100 has 72 divisors (see below), whose sum is σ = 155201660208. Its totient is φ = 14023808000.
The previous prime is 53115203059. The next prime is 53115203107. The reversal of 53115203100 is 130251135.
It is a super-2 number, since 2×531152031002 (a number of 22 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (53115203107) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 846189 + ... + 906788.
It is an arithmetic number, because the mean of its divisors is an integer number (2155578614).
Almost surely, 253115203100 is an apocalyptic number.
53115203100 is a gapful number since it is divisible by the number (50) formed by its first and last digit.
It is an amenable number.
53115203100 is an abundant number, since it is smaller than the sum of its proper divisors (102086457108).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
53115203100 is a wasteful number, since it uses less digits than its factorization.
53115203100 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1753095 (or 1753088 counting only the distinct ones).
The product of its (nonzero) digits is 450, while the sum is 21.
Adding to 53115203100 its reverse (130251135), we get a palindrome (53245454235).
The spelling of 53115203100 in words is "fifty-three billion, one hundred fifteen million, two hundred three thousand, one hundred".
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