Base | Representation |
---|---|
bin | 11000001010000100011000… |
… | …11110001110111010000000 |
3 | 20222002110111012211210200221 |
4 | 30011002030132032322000 |
5 | 23430324401114040134 |
6 | 304552051211352424 |
7 | 14121655242560110 |
oct | 1405021436167200 |
9 | 228073435753627 |
10 | 53122512252544 |
11 | 15a211492a1459 |
12 | 5b5b5b9a52714 |
13 | 238457ba695b7 |
14 | d19201367040 |
15 | 621c89ba55b4 |
hex | 30508c78ee80 |
53122512252544 has 64 divisors (see below), whose sum is σ = 120949907126400. Its totient is φ = 22766540590080.
The previous prime is 53122512252517. The next prime is 53122512252611. The reversal of 53122512252544 is 44525221522135.
It is a tau number, because it is divible by the number of its divisors (64).
It is a self number, because there is not a number n which added to its sum of digits gives 53122512252544.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 97597789 + ... + 98140579.
It is an arithmetic number, because the mean of its divisors is an integer number (1889842298850).
Almost surely, 253122512252544 is an apocalyptic number.
It is an amenable number.
53122512252544 is an abundant number, since it is smaller than the sum of its proper divisors (67827394873856).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
53122512252544 is a wasteful number, since it uses less digits than its factorization.
53122512252544 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 652041 (or 652029 counting only the distinct ones).
The product of its digits is 960000, while the sum is 43.
Adding to 53122512252544 its reverse (44525221522135), we get a palindrome (97647733774679).
The spelling of 53122512252544 in words is "fifty-three trillion, one hundred twenty-two billion, five hundred twelve million, two hundred fifty-two thousand, five hundred forty-four".
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