Base | Representation |
---|---|
bin | 111100011001010110101110… |
… | …0101110000111010101000010 |
3 | 2120200000001000200112222110211 |
4 | 1320302231130232013111002 |
5 | 1024113001211440331200 |
6 | 5121513013304344334 |
7 | 216620400023166364 |
oct | 17062553456072502 |
9 | 2520001020488424 |
10 | 531250355402050 |
11 | 144300012a57869 |
12 | 4b6bba651750aa |
13 | 19a5790298560b |
14 | 9528923936d34 |
15 | 416409305baba |
hex | 1e32b5cb87542 |
531250355402050 has 24 divisors (see below), whose sum is σ = 998312523541956. Its totient is φ = 210309419043840.
The previous prime is 531250355402047. The next prime is 531250355402093. The reversal of 531250355402050 is 50204553052135.
It can be written as a sum of positive squares in 6 ways, for example, as 85996930543209 + 445253424858841 = 9273453^2 + 21101029^2 .
It is a super-2 number, since 2×5312503554020502 (a number of 30 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 531250355401994 and 531250355402012.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 54768073027 + ... + 54768082726.
Almost surely, 2531250355402050 is an apocalyptic number.
531250355402050 is a gapful number since it is divisible by the number (50) formed by its first and last digit.
531250355402050 is a deficient number, since it is larger than the sum of its proper divisors (467062168139906).
531250355402050 is a wasteful number, since it uses less digits than its factorization.
531250355402050 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 109536155862 (or 109536155857 counting only the distinct ones).
The product of its (nonzero) digits is 450000, while the sum is 40.
The spelling of 531250355402050 in words is "five hundred thirty-one trillion, two hundred fifty billion, three hundred fifty-five million, four hundred two thousand, fifty".
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