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531314020213 is a prime number
BaseRepresentation
bin1111011101101001100…
…10001000111101110101
31212210102012001202110221
413232310302020331311
532201112342121323
61044025435214341
753246312441044
oct7566462107565
91783365052427
10531314020213
11195368a05349
1286b7bba73b1
133b144819512
141ba03d9c55b
15dc49cbb55d
hex7bb4c88f75

531314020213 has 2 divisors, whose sum is σ = 531314020214. Its totient is φ = 531314020212.

The previous prime is 531314020183. The next prime is 531314020241. The reversal of 531314020213 is 312020413135.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 330145623889 + 201168396324 = 574583^2 + 448518^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-531314020213 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (531314020253) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 265657010106 + 265657010107.

It is an arithmetic number, because the mean of its divisors is an integer number (265657010107).

Almost surely, 2531314020213 is an apocalyptic number.

It is an amenable number.

531314020213 is a deficient number, since it is larger than the sum of its proper divisors (1).

531314020213 is an equidigital number, since it uses as much as digits as its factorization.

531314020213 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2160, while the sum is 25.

Adding to 531314020213 its reverse (312020413135), we get a palindrome (843334433348).

The spelling of 531314020213 in words is "five hundred thirty-one billion, three hundred fourteen million, twenty thousand, two hundred thirteen".