Base | Representation |
---|---|
bin | 11000001010011010100100… |
… | …10011101001001110011101 |
3 | 20222010121020011211002210021 |
4 | 30011031102103221032131 |
5 | 23431023243323101000 |
6 | 305001341031512141 |
7 | 14122556331033334 |
oct | 1405152223511635 |
9 | 228117204732707 |
10 | 53134421300125 |
11 | 15a261aa681140 |
12 | 5b61982228651 |
13 | 2385729107809 |
14 | d19a10c6ad1b |
15 | 62223545c11a |
hex | 3053524e939d |
53134421300125 has 64 divisors (see below), whose sum is σ = 78463581251328. Its totient is φ = 35483009280000.
The previous prime is 53134421300069. The next prime is 53134421300179. The reversal of 53134421300125 is 52100312443135.
It is not a de Polignac number, because 53134421300125 - 29 = 53134421299613 is a prime.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 26762727 + ... + 28679476.
It is an arithmetic number, because the mean of its divisors is an integer number (1225993457052).
Almost surely, 253134421300125 is an apocalyptic number.
53134421300125 is a gapful number since it is divisible by the number (55) formed by its first and last digit.
It is an amenable number.
53134421300125 is a deficient number, since it is larger than the sum of its proper divisors (25329159951203).
53134421300125 is a wasteful number, since it uses less digits than its factorization.
53134421300125 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 55442287 (or 55442277 counting only the distinct ones).
The product of its (nonzero) digits is 43200, while the sum is 34.
The spelling of 53134421300125 in words is "fifty-three trillion, one hundred thirty-four billion, four hundred twenty-one million, three hundred thousand, one hundred twenty-five".
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