Base | Representation |
---|---|
bin | 1001111001011110… |
… | …11001101001000001 |
3 | 111201100021111022121 |
4 | 10330233121221001 |
5 | 41340342313144 |
6 | 2235150004241 |
7 | 245454322213 |
oct | 47457315101 |
9 | 14640244277 |
10 | 5314026049 |
11 | 22876a1472 |
12 | 10437a6681 |
13 | 668c2a917 |
14 | 385a865b3 |
15 | 2117d6384 |
hex | 13cbd9a41 |
5314026049 has 2 divisors, whose sum is σ = 5314026050. Its totient is φ = 5314026048.
The previous prime is 5314026037. The next prime is 5314026061. The reversal of 5314026049 is 9406204135.
It is a happy number.
It is a balanced prime because it is at equal distance from previous prime (5314026037) and next prime (5314026061).
It can be written as a sum of positive squares in only one way, i.e., 3380841025 + 1933185024 = 58145^2 + 43968^2 .
It is a cyclic number.
It is not a de Polignac number, because 5314026049 - 215 = 5313993281 is a prime.
It is not a weakly prime, because it can be changed into another prime (5314026089) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2657013024 + 2657013025.
It is an arithmetic number, because the mean of its divisors is an integer number (2657013025).
Almost surely, 25314026049 is an apocalyptic number.
It is an amenable number.
5314026049 is a deficient number, since it is larger than the sum of its proper divisors (1).
5314026049 is an equidigital number, since it uses as much as digits as its factorization.
5314026049 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 25920, while the sum is 34.
The square root of 5314026049 is about 72897.3665436551. The cubic root of 5314026049 is about 1745.0500719342.
The spelling of 5314026049 in words is "five billion, three hundred fourteen million, twenty-six thousand, forty-nine".
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