Base | Representation |
---|---|
bin | 11000001100010100110100… |
… | …00101011110100110011100 |
3 | 20222100212121221220022102202 |
4 | 30012022122011132212130 |
5 | 23433112200303234310 |
6 | 305051433211511032 |
7 | 14130401556200651 |
oct | 1406123205364634 |
9 | 228325557808382 |
10 | 53200050055580 |
11 | 15a5101837450a |
12 | 5b72639158478 |
13 | 238b987a4981c |
14 | d1cc790d1c28 |
15 | 623cc6e143a5 |
hex | 30629a15e99c |
53200050055580 has 24 divisors (see below), whose sum is σ = 111773330600400. Its totient is φ = 21269881834880.
The previous prime is 53200050055571. The next prime is 53200050055619. The reversal of 53200050055580 is 8555005000235.
It is a super-3 number, since 3×532000500555803 (a number of 42 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 633593681 + ... + 633677640.
It is an arithmetic number, because the mean of its divisors is an integer number (4657222108350).
Almost surely, 253200050055580 is an apocalyptic number.
It is an amenable number.
53200050055580 is an abundant number, since it is smaller than the sum of its proper divisors (58573280544820).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
53200050055580 is a wasteful number, since it uses less digits than its factorization.
53200050055580 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1267273429 (or 1267273427 counting only the distinct ones).
The product of its (nonzero) digits is 150000, while the sum is 38.
The spelling of 53200050055580 in words is "fifty-three trillion, two hundred billion, fifty million, fifty-five thousand, five hundred eighty".
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