Base | Representation |
---|---|
bin | 110001100011100100… |
… | …011110001111101000 |
3 | 12002100022012210210221 |
4 | 301203210132033220 |
5 | 1332433242104000 |
6 | 40235553215424 |
7 | 3562411332532 |
oct | 614344361750 |
9 | 162308183727 |
10 | 53210113000 |
11 | 206257a3500 |
12 | a38bb61574 |
13 | 502cb3c685 |
14 | 280abcc852 |
15 | 15b65de61a |
hex | c6391e3e8 |
53210113000 has 96 divisors (see below), whose sum is σ = 136860239880. Its totient is φ = 19349088000.
The previous prime is 53210112983. The next prime is 53210113051. The reversal of 53210113000 is 31101235.
53210113000 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It can be written as a sum of positive squares in 4 ways, for example, as 18888104356 + 34322008644 = 137434^2 + 185262^2 .
It is a super-2 number, since 2×532101130002 (a number of 22 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 98877 + ... + 340876.
Almost surely, 253210113000 is an apocalyptic number.
53210113000 is a gapful number since it is divisible by the number (50) formed by its first and last digit.
It is an amenable number.
53210113000 is an abundant number, since it is smaller than the sum of its proper divisors (83650126880).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
53210113000 is a wasteful number, since it uses less digits than its factorization.
53210113000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 439796 (or 439771 counting only the distinct ones).
The product of its (nonzero) digits is 90, while the sum is 16.
Adding to 53210113000 its reverse (31101235), we get a palindrome (53241214235).
The spelling of 53210113000 in words is "fifty-three billion, two hundred ten million, one hundred thirteen thousand".
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