Base | Representation |
---|---|
bin | 100110101110011111001… |
… | …1111011000010011011111 |
3 | 200211211100002000121202202 |
4 | 1031130332133120103133 |
5 | 1144201001300040101 |
6 | 15153043443042115 |
7 | 1056352555056506 |
oct | 115347637302337 |
9 | 20754302017682 |
10 | 5322512893151 |
11 | 17722a0852683 |
12 | 71b65697033b |
13 | 2c7bac09260c |
14 | 14587a81983d |
15 | 936b657236b |
hex | 4d73e7d84df |
5322512893151 has 2 divisors, whose sum is σ = 5322512893152. Its totient is φ = 5322512893150.
The previous prime is 5322512893133. The next prime is 5322512893153. The reversal of 5322512893151 is 1513982152235.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5322512893151 is a prime.
Together with 5322512893153, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 5322512893096 and 5322512893105.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5322512893153) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2661256446575 + 2661256446576.
It is an arithmetic number, because the mean of its divisors is an integer number (2661256446576).
Almost surely, 25322512893151 is an apocalyptic number.
5322512893151 is a deficient number, since it is larger than the sum of its proper divisors (1).
5322512893151 is an equidigital number, since it uses as much as digits as its factorization.
5322512893151 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 648000, while the sum is 47.
The spelling of 5322512893151 in words is "five trillion, three hundred twenty-two billion, five hundred twelve million, eight hundred ninety-three thousand, one hundred fifty-one".
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