Base | Representation |
---|---|
bin | 100110101110111101111… |
… | …0111001001100100000000 |
3 | 200211220222211110211000211 |
4 | 1031131323313021210000 |
5 | 1144210103342100100 |
6 | 15153333543523504 |
7 | 1056420226633156 |
oct | 115357367114400 |
9 | 20756884424024 |
10 | 5323542534400 |
11 | 1772779a81362 |
12 | 71b8a3759594 |
13 | 2c80144aa3ac |
14 | 1459374813d6 |
15 | 93726b5b1ba |
hex | 4d77bdc9900 |
5323542534400 has 54 divisors (see below), whose sum is σ = 13176599592002. Its totient is φ = 2129417011200.
The previous prime is 5323542534383. The next prime is 5323542534421. The reversal of 5323542534400 is 44352453235.
It can be written as a sum of positive squares in 3 ways, for example, as 1856438950144 + 3467103584256 = 1362512^2 + 1862016^2 .
It is a Harshad number since it is a multiple of its sum of digits (40).
It is an unprimeable number.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 415895361 + ... + 415908160.
Almost surely, 25323542534400 is an apocalyptic number.
5323542534400 is a gapful number since it is divisible by the number (50) formed by its first and last digit.
It is an amenable number.
5323542534400 is an abundant number, since it is smaller than the sum of its proper divisors (7853057057602).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
5323542534400 is an equidigital number, since it uses as much as digits as its factorization.
5323542534400 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 831803547 (or 831803528 counting only the distinct ones).
The product of its (nonzero) digits is 864000, while the sum is 40.
Adding to 5323542534400 its reverse (44352453235), we get a palindrome (5367894987635).
The spelling of 5323542534400 in words is "five trillion, three hundred twenty-three billion, five hundred forty-two million, five hundred thirty-four thousand, four hundred".
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