Base | Representation |
---|---|
bin | 11000001101110000000000… |
… | …11001011010111111101111 |
3 | 20222112120000010221011002101 |
4 | 30012320000121122333233 |
5 | 23434412433331344413 |
6 | 305130131423035531 |
7 | 14134054065102124 |
oct | 1406700031327757 |
9 | 228476003834071 |
10 | 53249011199983 |
11 | 15a6a862694a15 |
12 | 5b8002213bba7 |
13 | 239348b4c66a1 |
14 | d213a187c74b |
15 | 6251e049eedd |
hex | 306e0065afef |
53249011199983 has 2 divisors, whose sum is σ = 53249011199984. Its totient is φ = 53249011199982.
The previous prime is 53249011199947. The next prime is 53249011200019. The reversal of 53249011199983 is 38999111094235.
It is a balanced prime because it is at equal distance from previous prime (53249011199947) and next prime (53249011200019).
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-53249011199983 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (53249011199933) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26624505599991 + 26624505599992.
It is an arithmetic number, because the mean of its divisors is an integer number (26624505599992).
Almost surely, 253249011199983 is an apocalyptic number.
53249011199983 is a deficient number, since it is larger than the sum of its proper divisors (1).
53249011199983 is an equidigital number, since it uses as much as digits as its factorization.
53249011199983 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 18895680, while the sum is 64.
The spelling of 53249011199983 in words is "fifty-three trillion, two hundred forty-nine billion, eleven million, one hundred ninety-nine thousand, nine hundred eighty-three".
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