Base | Representation |
---|---|
bin | 111100100110011101010001… |
… | …0111001101101110010010100 |
3 | 2120220101012010100122100102201 |
4 | 1321030322202321231302110 |
5 | 1024332002200240122200 |
6 | 5125412150020214244 |
7 | 220164446531022415 |
oct | 17114724271556224 |
9 | 2526335110570381 |
10 | 533051124145300 |
11 | 144934791a69652 |
12 | 4b950a66b3a384 |
13 | 19b58675258687 |
14 | 958bb5245580c |
15 | 4195d3a315c6a |
hex | 1e4cea2e6dc94 |
533051124145300 has 72 divisors (see below), whose sum is σ = 1178685748783872. Its totient is φ = 209172591888000.
The previous prime is 533051124145279. The next prime is 533051124145307. The reversal of 533051124145300 is 3541421150335.
It is a self number, because there is not a number n which added to its sum of digits gives 533051124145300.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (533051124145307) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 38719665 + ... + 50648935.
It is an arithmetic number, because the mean of its divisors is an integer number (16370635399776).
Almost surely, 2533051124145300 is an apocalyptic number.
533051124145300 is a gapful number since it is divisible by the number (50) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 533051124145300, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (589342874391936).
533051124145300 is an abundant number, since it is smaller than the sum of its proper divisors (645634624638572).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
533051124145300 is a wasteful number, since it uses less digits than its factorization.
533051124145300 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11937769 (or 11937762 counting only the distinct ones).
The product of its (nonzero) digits is 108000, while the sum is 37.
Adding to 533051124145300 its reverse (3541421150335), we get a palindrome (536592545295635).
The spelling of 533051124145300 in words is "five hundred thirty-three trillion, fifty-one billion, one hundred twenty-four million, one hundred forty-five thousand, three hundred".
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