Base | Representation |
---|---|
bin | 100110110011111011101… |
… | …0101011011110000010111 |
3 | 200212221111211220122210002 |
4 | 1031213313111123300113 |
5 | 1144343422211133044 |
6 | 15202255520121515 |
7 | 1060245355636043 |
oct | 115476725336027 |
9 | 20787454818702 |
10 | 5334204005399 |
11 | 177725010a315 |
12 | 72197a16629b |
13 | 2c9023236b09 |
14 | 1462693cd023 |
15 | 93b4cb2a74e |
hex | 4d9f755bc17 |
5334204005399 has 2 divisors, whose sum is σ = 5334204005400. Its totient is φ = 5334204005398.
The previous prime is 5334204005387. The next prime is 5334204005401. The reversal of 5334204005399 is 9935004024335.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5334204005399 is a prime.
It is a super-2 number, since 2×53342040053992 (a number of 26 digits) contains 22 as substring.
Together with 5334204005401, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5334204005309) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2667102002699 + 2667102002700.
It is an arithmetic number, because the mean of its divisors is an integer number (2667102002700).
Almost surely, 25334204005399 is an apocalyptic number.
5334204005399 is a deficient number, since it is larger than the sum of its proper divisors (1).
5334204005399 is an equidigital number, since it uses as much as digits as its factorization.
5334204005399 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1749600, while the sum is 47.
The spelling of 5334204005399 in words is "five trillion, three hundred thirty-four billion, two hundred four million, five thousand, three hundred ninety-nine".
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