Base | Representation |
---|---|
bin | 11000010000110000101010… |
… | …10111000111110011000100 |
3 | 20222220102222102110222121020 |
4 | 30020120111113013303010 |
5 | 23443111300141234300 |
6 | 305245435030551140 |
7 | 14144405152402623 |
oct | 1410302527076304 |
9 | 228812872428536 |
10 | 53352442133700 |
11 | 15aaa709764326 |
12 | 5b98088b084b0 |
13 | 23a0162a6cc08 |
14 | d263b443d6ba |
15 | 627c45a028a0 |
hex | 3086155c7cc4 |
53352442133700 has 36 divisors (see below), whose sum is σ = 154366399241040. Its totient is φ = 14227317902240.
The previous prime is 53352442133689. The next prime is 53352442133777. The reversal of 53352442133700 is 733124425335.
It is a happy number.
It is a super-3 number, since 3×533524421337003 (a number of 42 digits) contains 333 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 88920736590 + ... + 88920737189.
Almost surely, 253352442133700 is an apocalyptic number.
53352442133700 is a gapful number since it is divisible by the number (50) formed by its first and last digit.
It is an amenable number.
53352442133700 is an abundant number, since it is smaller than the sum of its proper divisors (101013957107340).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
53352442133700 is a wasteful number, since it uses less digits than its factorization.
53352442133700 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 177841473796 (or 177841473789 counting only the distinct ones).
The product of its (nonzero) digits is 907200, while the sum is 42.
The spelling of 53352442133700 in words is "fifty-three trillion, three hundred fifty-two billion, four hundred forty-two million, one hundred thirty-three thousand, seven hundred".
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