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5335330519997 is a prime number
BaseRepresentation
bin100110110100011101001…
…1110101111101110111101
3200220001102100122112021222
41031220322132233232331
51144403224103114442
615203003401203125
71060315315103132
oct115507236575675
920801370575258
105335330519997
111777778a94415
127220334904a5
132c917273c1ba
14146334c70589
1593bb699c8d2
hex4da3a7afbbd

5335330519997 has 2 divisors, whose sum is σ = 5335330519998. Its totient is φ = 5335330519996.

The previous prime is 5335330519969. The next prime is 5335330520059. The reversal of 5335330519997 is 7999150335335.

It is a happy number.

It is an a-pointer prime, because the next prime (5335330520059) can be obtained adding 5335330519997 to its sum of digits (62).

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 3408506133796 + 1926824386201 = 1846214^2 + 1388101^2 .

It is a cyclic number.

It is not a de Polignac number, because 5335330519997 - 28 = 5335330519741 is a prime.

It is a super-2 number, since 2×53353305199972 (a number of 26 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5335330519397) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2667665259998 + 2667665259999.

It is an arithmetic number, because the mean of its divisors is an integer number (2667665259999).

Almost surely, 25335330519997 is an apocalyptic number.

It is an amenable number.

5335330519997 is a deficient number, since it is larger than the sum of its proper divisors (1).

5335330519997 is an equidigital number, since it uses as much as digits as its factorization.

5335330519997 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 51667875, while the sum is 62.

The spelling of 5335330519997 in words is "five trillion, three hundred thirty-five billion, three hundred thirty million, five hundred nineteen thousand, nine hundred ninety-seven".