Base | Representation |
---|---|
bin | 11000010001001001000001… |
… | …00110011100010101011111 |
3 | 20222221200201112111221120222 |
4 | 30020210200212130111133 |
5 | 23443320033443214442 |
6 | 305255440204431555 |
7 | 14145350140135433 |
oct | 1410444046342537 |
9 | 228850645457528 |
10 | 53365515601247 |
11 | 16005208358a63 |
12 | 5b9a7172485bb |
13 | 23a1467425825 |
14 | d26c948509c3 |
15 | 62825d6178d2 |
hex | 30892099c55f |
53365515601247 has 2 divisors, whose sum is σ = 53365515601248. Its totient is φ = 53365515601246.
The previous prime is 53365515601217. The next prime is 53365515601249. The reversal of 53365515601247 is 74210651556335.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 53365515601247 - 226 = 53365448492383 is a prime.
Together with 53365515601249, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (53365515601249) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26682757800623 + 26682757800624.
It is an arithmetic number, because the mean of its divisors is an integer number (26682757800624).
Almost surely, 253365515601247 is an apocalyptic number.
53365515601247 is a deficient number, since it is larger than the sum of its proper divisors (1).
53365515601247 is an equidigital number, since it uses as much as digits as its factorization.
53365515601247 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 11340000, while the sum is 53.
The spelling of 53365515601247 in words is "fifty-three trillion, three hundred sixty-five billion, five hundred fifteen million, six hundred one thousand, two hundred forty-seven".
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