Search a number
-
+
534335104194317 is a prime number
BaseRepresentation
bin111100101111110011001011…
…0000100111001011100001101
32121001220221022010121222020222
41321133212112010321130031
51030014021243133204232
65132234054052521125
7220356303000250466
oct17137462604713415
92531827263558228
10534335104194317
1114528a277259528
124bb198813201a5
1319c1c77940287a
1495d3d58157d6d
1541b9437b03d12
hex1e5f99613970d

534335104194317 has 2 divisors, whose sum is σ = 534335104194318. Its totient is φ = 534335104194316.

The previous prime is 534335104194293. The next prime is 534335104194319. The reversal of 534335104194317 is 713491401533435.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 509748292691236 + 24586811503081 = 22577606^2 + 4958509^2 .

It is a cyclic number.

It is not a de Polignac number, because 534335104194317 - 216 = 534335104128781 is a prime.

Together with 534335104194319, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (534335104194319) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 267167552097158 + 267167552097159.

It is an arithmetic number, because the mean of its divisors is an integer number (267167552097159).

Almost surely, 2534335104194317 is an apocalyptic number.

It is an amenable number.

534335104194317 is a deficient number, since it is larger than the sum of its proper divisors (1).

534335104194317 is an equidigital number, since it uses as much as digits as its factorization.

534335104194317 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 8164800, while the sum is 53.

The spelling of 534335104194317 in words is "five hundred thirty-four trillion, three hundred thirty-five billion, one hundred four million, one hundred ninety-four thousand, three hundred seventeen".