Base | Representation |
---|---|
bin | 11000010011001010101110… |
… | …01100110101111110000000 |
3 | 21000012100110120000112010001 |
4 | 30021211113030311332000 |
5 | 24000440142141122422 |
6 | 305351434115245344 |
7 | 14153363600212405 |
oct | 1411452714657600 |
9 | 230170416015101 |
10 | 53435151114112 |
11 | 160317a1830499 |
12 | 5bb010bba9854 |
13 | 23a7bb41b3c01 |
14 | d2a3bcca82ac |
15 | 629e86c2c227 |
hex | 309957335f80 |
53435151114112 has 128 divisors (see below), whose sum is σ = 115163143329600. Its totient is φ = 24620691701760.
The previous prime is 53435151114109. The next prime is 53435151114161. The reversal of 53435151114112 is 21141115153435.
It is a tau number, because it is divible by the number of its divisors (128).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 38332062 + ... + 39701602.
Almost surely, 253435151114112 is an apocalyptic number.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 53435151114112, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (57581571664800).
53435151114112 is an abundant number, since it is smaller than the sum of its proper divisors (61727992215488).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
53435151114112 is a wasteful number, since it uses less digits than its factorization.
53435151114112 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1370064 (or 1370052 counting only the distinct ones).
The product of its digits is 36000, while the sum is 37.
Adding to 53435151114112 its reverse (21141115153435), we get a palindrome (74576266267547).
The spelling of 53435151114112 in words is "fifty-three trillion, four hundred thirty-five billion, one hundred fifty-one million, one hundred fourteen thousand, one hundred twelve".
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