Base | Representation |
---|---|
bin | 1111100110100100100… |
… | …01000111000011011000 |
3 | 1220020202222120221001101 |
4 | 13303102101013003120 |
5 | 32240420013123100 |
6 | 1050141013401144 |
7 | 53506101540631 |
oct | 7632221070330 |
9 | 1806688527041 |
10 | 536103645400 |
11 | 1973a6593674 |
12 | 87a980391b4 |
13 | 3b728bca76b |
14 | 1bd3a13a888 |
15 | de2a51986a |
hex | 7cd24470d8 |
536103645400 has 48 divisors (see below), whose sum is σ = 1289421712800. Its totient is φ = 207046922880.
The previous prime is 536103645379. The next prime is 536103645491. The reversal of 536103645400 is 4546301635.
It is a super-2 number, since 2×5361036454002 (a number of 24 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 536103645400.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 46210032 + ... + 46221631.
It is an arithmetic number, because the mean of its divisors is an integer number (26862952350).
Almost surely, 2536103645400 is an apocalyptic number.
536103645400 is a gapful number since it is divisible by the number (50) formed by its first and last digit.
It is an amenable number.
536103645400 is an abundant number, since it is smaller than the sum of its proper divisors (753318067400).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
536103645400 is a wasteful number, since it uses less digits than its factorization.
536103645400 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 92431708 (or 92431699 counting only the distinct ones).
The product of its (nonzero) digits is 129600, while the sum is 37.
The spelling of 536103645400 in words is "five hundred thirty-six billion, one hundred three million, six hundred forty-five thousand, four hundred".
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