Base | Representation |
---|---|
bin | 110001111011100010… |
… | …000101010111001010 |
3 | 12010101022200220011000 |
4 | 301323202011113022 |
5 | 1334244201434403 |
6 | 40343514115430 |
7 | 3605362446045 |
oct | 617342052712 |
9 | 163338626130 |
10 | 53612139978 |
11 | 20811723301 |
12 | a48271bb76 |
13 | 5095210767 |
14 | 284835dc5c |
15 | 15dba537a3 |
hex | c7b8855ca |
53612139978 has 64 divisors (see below), whose sum is σ = 124517232000. Its totient is φ = 17076552192.
The previous prime is 53612139943. The next prime is 53612139989. The reversal of 53612139978 is 87993121635.
53612139978 is a `hidden beast` number, since 5 + 3 + 612 + 13 + 9 + 9 + 7 + 8 = 666.
53612139978 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a Harshad number since it is a multiple of its sum of digits (54).
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 24568 + ... + 328371.
It is an arithmetic number, because the mean of its divisors is an integer number (1945581750).
Almost surely, 253612139978 is an apocalyptic number.
53612139978 is a gapful number since it is divisible by the number (58) formed by its first and last digit.
53612139978 is an abundant number, since it is smaller than the sum of its proper divisors (70905092022).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
53612139978 is a wasteful number, since it uses less digits than its factorization.
53612139978 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 353076 (or 353070 counting only the distinct ones).
The product of its digits is 2449440, while the sum is 54.
The spelling of 53612139978 in words is "fifty-three billion, six hundred twelve million, one hundred thirty-nine thousand, nine hundred seventy-eight".
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