53643407 has 2 divisors, whose sum is σ = 53643408. Its totient is φ = 53643406.

The previous prime is 53643397. The next prime is 53643409. The reversal of 53643407 is 70434635.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-53643407 is a prime.

It is a super-2 number, since 2×53643407² = 5755230229135298, which contains 22 as substring.

Together with 53643409, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (53643409) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26821703 + 26821704.

It is an arithmetic number, because the mean of its divisors is an integer number (26821704).

Almost surely, 2^53643407 is an apocalyptic number.

53643407 is a deficient number, since it is larger than the sum of its proper divisors (1).

53643407 is an equidigital number, since it uses as much as digits as its factorization.

53643407 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 30240, while the sum is 32.

The square root of 53643407 is about 7324.1659593431. The cubic root of 53643407 is about 377.1424786347.

The spelling of 53643407 in words is "fifty-three million, six hundred forty-three thousand, four hundred seven".