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5371267150 = 252711513033
BaseRepresentation
bin1010000000010011…
…10000100001001110
3111212022222122100101
411000021300201032
542000021022100
62244552521314
7250051005664
oct50011604116
914768878311
105371267150
112306a38567
12105a9b023a
13677a4cbb2
1438d506c34
1521684186a
hex14027084e

5371267150 has 24 divisors (see below), whose sum is σ = 10131275664. Its totient is φ = 2118244800.

The previous prime is 5371267123. The next prime is 5371267169. The reversal of 5371267150 is 517621735.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 752967 + ... + 760066.

It is an arithmetic number, because the mean of its divisors is an integer number (422136486).

Almost surely, 25371267150 is an apocalyptic number.

5371267150 is a gapful number since it is divisible by the number (50) formed by its first and last digit.

5371267150 is a deficient number, since it is larger than the sum of its proper divisors (4760008514).

5371267150 is a wasteful number, since it uses less digits than its factorization.

5371267150 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1513116 (or 1513111 counting only the distinct ones).

The product of its (nonzero) digits is 44100, while the sum is 37.

The square root of 5371267150 is about 73288.9292458281. The cubic root of 5371267150 is about 1751.2934274639.

Adding to 5371267150 its reverse (517621735), we get a palindrome (5888888885).

The spelling of 5371267150 in words is "five billion, three hundred seventy-one million, two hundred sixty-seven thousand, one hundred fifty".

Divisors: 1 2 5 10 25 50 71 142 355 710 1775 3550 1513033 3026066 7565165 15130330 37825825 75651650 107425343 214850686 537126715 1074253430 2685633575 5371267150