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5394141546551 is a prime number
BaseRepresentation
bin100111001111110101111…
…1001000000100000110111
3201002200012222222020002122
41032133223321000200313
51201334200213442201
615250011233430155
71064466566426012
oct116375371004067
921080188866078
105394141546551
11179a70830709a
1273150710b35b
13301885a65ab4
14149113864379
15954a9b41e1b
hex4e7ebe40837

5394141546551 has 2 divisors, whose sum is σ = 5394141546552. Its totient is φ = 5394141546550.

The previous prime is 5394141546511. The next prime is 5394141546553. The reversal of 5394141546551 is 1556451414935.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 5394141546551 - 242 = 996095035447 is a prime.

It is a super-2 number, since 2×53941415465512 (a number of 26 digits) contains 22 as substring.

Together with 5394141546553, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 5394141546493 and 5394141546502.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5394141546553) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2697070773275 + 2697070773276.

It is an arithmetic number, because the mean of its divisors is an integer number (2697070773276).

Almost surely, 25394141546551 is an apocalyptic number.

5394141546551 is a deficient number, since it is larger than the sum of its proper divisors (1).

5394141546551 is an equidigital number, since it uses as much as digits as its factorization.

5394141546551 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 6480000, while the sum is 53.

The spelling of 5394141546551 in words is "five trillion, three hundred ninety-four billion, one hundred forty-one million, five hundred forty-six thousand, five hundred fifty-one".