Base | Representation |
---|---|
bin | 1111101110010000100… |
… | …11000100101101011111 |
3 | 1220122102122121022110021 |
4 | 13313020103010231133 |
5 | 32322343211331411 |
6 | 1052102344453011 |
7 | 54013302516241 |
oct | 7671023045537 |
9 | 1818378538407 |
10 | 540231355231 |
11 | 199124575107 |
12 | 8884a47a167 |
13 | 3bc36115409 |
14 | 1c20c416091 |
15 | e0bcab9a71 |
hex | 7dc84c4b5f |
540231355231 has 2 divisors, whose sum is σ = 540231355232. Its totient is φ = 540231355230.
The previous prime is 540231355229. The next prime is 540231355253. The reversal of 540231355231 is 132553132045.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 540231355231 - 21 = 540231355229 is a prime.
It is a super-2 number, since 2×5402313552312 (a number of 24 digits) contains 22 as substring.
Together with 540231355229, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (540231355211) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 270115677615 + 270115677616.
It is an arithmetic number, because the mean of its divisors is an integer number (270115677616).
Almost surely, 2540231355231 is an apocalyptic number.
540231355231 is a deficient number, since it is larger than the sum of its proper divisors (1).
540231355231 is an equidigital number, since it uses as much as digits as its factorization.
540231355231 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54000, while the sum is 34.
Adding to 540231355231 its reverse (132553132045), we get a palindrome (672784487276).
The spelling of 540231355231 in words is "five hundred forty billion, two hundred thirty-one million, three hundred fifty-five thousand, two hundred thirty-one".
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