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540260555141 is a prime number
BaseRepresentation
bin1111101110010100000…
…10011101100110000101
31220122111200112211012102
413313022002131212011
532322423200231031
61052105310401445
754014105643206
oct7671202354605
91818450484172
10540260555141
11199139aa946a
1288858200285
133bc3c19a178
141c2122575ad
15e0c04367cb
hex7dca09d985

540260555141 has 2 divisors, whose sum is σ = 540260555142. Its totient is φ = 540260555140.

The previous prime is 540260555137. The next prime is 540260555143. The reversal of 540260555141 is 141555062045.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 307946195041 + 232314360100 = 554929^2 + 481990^2 .

It is a cyclic number.

It is not a de Polignac number, because 540260555141 - 22 = 540260555137 is a prime.

Together with 540260555143, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 540260555095 and 540260555104.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (540260555143) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 270130277570 + 270130277571.

It is an arithmetic number, because the mean of its divisors is an integer number (270130277571).

Almost surely, 2540260555141 is an apocalyptic number.

It is an amenable number.

540260555141 is a deficient number, since it is larger than the sum of its proper divisors (1).

540260555141 is an equidigital number, since it uses as much as digits as its factorization.

540260555141 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 120000, while the sum is 38.

The spelling of 540260555141 in words is "five hundred forty billion, two hundred sixty million, five hundred fifty-five thousand, one hundred forty-one".