Base | Representation |
---|---|
bin | 100111010111011101100… |
… | …1000010101100010011111 |
3 | 201011020110021120222111221 |
4 | 1032232323020111202133 |
5 | 1202121202324203211 |
6 | 15301314555554211 |
7 | 1065616213445104 |
oct | 116567310254237 |
9 | 21136407528457 |
10 | 5410503350431 |
11 | 17a66440a9563 |
12 | 73471275b967 |
13 | 303292778b5a |
14 | 149c26896aab |
15 | 95b162a3c71 |
hex | 4ebbb21589f |
5410503350431 has 2 divisors, whose sum is σ = 5410503350432. Its totient is φ = 5410503350430.
The previous prime is 5410503350429. The next prime is 5410503350467. The reversal of 5410503350431 is 1340533050145.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5410503350431 - 21 = 5410503350429 is a prime.
It is a super-3 number, since 3×54105033504313 (a number of 39 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
Together with 5410503350429, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5410503350401) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2705251675215 + 2705251675216.
It is an arithmetic number, because the mean of its divisors is an integer number (2705251675216).
Almost surely, 25410503350431 is an apocalyptic number.
5410503350431 is a deficient number, since it is larger than the sum of its proper divisors (1).
5410503350431 is an equidigital number, since it uses as much as digits as its factorization.
5410503350431 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54000, while the sum is 34.
The spelling of 5410503350431 in words is "five trillion, four hundred ten billion, five hundred three million, three hundred fifty thousand, four hundred thirty-one".
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