Base | Representation |
---|---|
bin | 100111010111110011100… |
… | …0011010001110000000111 |
3 | 201011022100122010220212112 |
4 | 1032233213003101300013 |
5 | 1202124204444043303 |
6 | 15301520041411235 |
7 | 1065643401653621 |
oct | 116574703216007 |
9 | 21138318126775 |
10 | 5411240221703 |
11 | 17a6992041888 |
12 | 734899499b1b |
13 | 30337c327964 |
14 | 149c966abc11 |
15 | 95b5ad0b0d8 |
hex | 4ebe70d1c07 |
5411240221703 has 2 divisors, whose sum is σ = 5411240221704. Its totient is φ = 5411240221702.
The previous prime is 5411240221691. The next prime is 5411240221753. The reversal of 5411240221703 is 3071220421145.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5411240221703 - 222 = 5411236027399 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 5411240221703.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5411240221753) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2705620110851 + 2705620110852.
It is an arithmetic number, because the mean of its divisors is an integer number (2705620110852).
Almost surely, 25411240221703 is an apocalyptic number.
5411240221703 is a deficient number, since it is larger than the sum of its proper divisors (1).
5411240221703 is an equidigital number, since it uses as much as digits as its factorization.
5411240221703 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 13440, while the sum is 32.
Adding to 5411240221703 its reverse (3071220421145), we get a palindrome (8482460642848).
The spelling of 5411240221703 in words is "five trillion, four hundred eleven billion, two hundred forty million, two hundred twenty-one thousand, seven hundred three".
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