Base | Representation |
---|---|
bin | 11000101001110001101111… |
… | …01010100101111011100000 |
3 | 21002221121200021011212222121 |
4 | 30110320313222211323200 |
5 | 24101202144321404100 |
6 | 311144353141314024 |
7 | 14263455113300635 |
oct | 1424706752457340 |
9 | 232847607155877 |
10 | 54212011122400 |
11 | 16301203a7999a |
12 | 60b6798a05914 |
13 | 243322b097aa1 |
14 | d55c37d0018c |
15 | 6402a37aa51a |
hex | 314e37aa5ee0 |
54212011122400 has 72 divisors (see below), whose sum is σ = 132392496119184. Its totient is φ = 21677034009600.
The previous prime is 54212011122361. The next prime is 54212011122421. The reversal of 54212011122400 is 422111021245.
It is a Harshad number since it is a multiple of its sum of digits (25).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 9907117 + ... + 14372716.
It is an arithmetic number, because the mean of its divisors is an integer number (1838784668322).
Almost surely, 254212011122400 is an apocalyptic number.
54212011122400 is a gapful number since it is divisible by the number (50) formed by its first and last digit.
It is an amenable number.
54212011122400 is an abundant number, since it is smaller than the sum of its proper divisors (78180484996784).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
54212011122400 is a wasteful number, since it uses less digits than its factorization.
54212011122400 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 24282644 (or 24282631 counting only the distinct ones).
The product of its (nonzero) digits is 1280, while the sum is 25.
Adding to 54212011122400 its reverse (422111021245), we get a palindrome (54634122143645).
The spelling of 54212011122400 in words is "fifty-four trillion, two hundred twelve billion, eleven million, one hundred twenty-two thousand, four hundred".
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