Base | Representation |
---|---|
bin | 100000011000100… |
… | …100011000110101 |
3 | 1101212100002010221 |
4 | 200120210120311 |
5 | 2103041431123 |
6 | 125525014341 |
7 | 16315033201 |
oct | 4030443065 |
9 | 1355302127 |
10 | 543311413 |
11 | 2597599a7 |
12 | 131b543b1 |
13 | 8873ac58 |
14 | 5222bb01 |
15 | 32a7125d |
hex | 20624635 |
543311413 has 2 divisors, whose sum is σ = 543311414. Its totient is φ = 543311412.
The previous prime is 543311411. The next prime is 543311467. The reversal of 543311413 is 314113345.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 420168004 + 123143409 = 20498^2 + 11097^2 .
It is a cyclic number.
It is not a de Polignac number, because 543311413 - 21 = 543311411 is a prime.
Together with 543311411, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (543311411) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (11) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 271655706 + 271655707.
It is an arithmetic number, because the mean of its divisors is an integer number (271655707).
Almost surely, 2543311413 is an apocalyptic number.
It is an amenable number.
543311413 is a deficient number, since it is larger than the sum of its proper divisors (1).
543311413 is an equidigital number, since it uses as much as digits as its factorization.
543311413 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 2160, while the sum is 25.
The square root of 543311413 is about 23309.0414431825. The cubic root of 543311413 is about 815.9864417882.
Adding to 543311413 its reverse (314113345), we get a palindrome (857424758).
The spelling of 543311413 in words is "five hundred forty-three million, three hundred eleven thousand, four hundred thirteen".
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