Base | Representation |
---|---|
bin | 100111110111111110100… |
… | …0101110101100000101110 |
3 | 201101220200120202021110122 |
4 | 1033233331011311200232 |
5 | 1204242203320433300 |
6 | 15353343440004542 |
7 | 1103640446605541 |
oct | 117577505654056 |
9 | 21356616667418 |
10 | 5480329467950 |
11 | 18232161270a7 |
12 | 74615b300752 |
13 | 309a3cb81c5c |
14 | 14d36c368858 |
15 | 978514b8c85 |
hex | 4fbfd17582e |
5480329467950 has 48 divisors (see below), whose sum is σ = 10730191817520. Its totient is φ = 2076701541120.
The previous prime is 5480329467947. The next prime is 5480329467959. The reversal of 5480329467950 is 597649230845.
It is a super-2 number, since 2×54803294679502 (a number of 26 digits) contains 22 as substring.
It is a Curzon number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5480329467959) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 66151754 + ... + 66234546.
It is an arithmetic number, because the mean of its divisors is an integer number (223545662865).
Almost surely, 25480329467950 is an apocalyptic number.
5480329467950 is a gapful number since it is divisible by the number (50) formed by its first and last digit.
5480329467950 is a deficient number, since it is larger than the sum of its proper divisors (5249862349570).
5480329467950 is a wasteful number, since it uses less digits than its factorization.
5480329467950 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 152501 (or 152496 counting only the distinct ones).
The product of its (nonzero) digits is 65318400, while the sum is 62.
The spelling of 5480329467950 in words is "five trillion, four hundred eighty billion, three hundred twenty-nine million, four hundred sixty-seven thousand, nine hundred fifty".
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