Base | Representation |
---|---|
bin | 1111111110110011001… |
… | …11000101110110100010 |
3 | 1221111100112122010000002 |
4 | 13333121213011312202 |
5 | 32444040102000200 |
6 | 1100131454300002 |
7 | 54446333602163 |
oct | 7773147056642 |
9 | 1844315563002 |
10 | 549111750050 |
11 | 1a19712a4186 |
12 | 8a5084b7602 |
13 | 3ca1cb793c6 |
14 | 1c8119b576a |
15 | e43c51cbd5 |
hex | 7fd99c5da2 |
549111750050 has 24 divisors (see below), whose sum is σ = 1021602358800. Its totient is φ = 219589968080.
The previous prime is 549111750041. The next prime is 549111750053. The reversal of 549111750050 is 50057111945.
It is a junction number, because it is equal to n+sod(n) for n = 549111749986 and 549111750013.
It is not an unprimeable number, because it can be changed into a prime (549111750053) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 1165340 + ... + 1567239.
It is an arithmetic number, because the mean of its divisors is an integer number (42566764950).
Almost surely, 2549111750050 is an apocalyptic number.
549111750050 is a gapful number since it is divisible by the number (50) formed by its first and last digit.
549111750050 is a deficient number, since it is larger than the sum of its proper divisors (472490608750).
549111750050 is a wasteful number, since it uses less digits than its factorization.
549111750050 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2736610 (or 2736605 counting only the distinct ones).
The product of its (nonzero) digits is 31500, while the sum is 38.
Adding to 549111750050 its reverse (50057111945), we get a palindrome (599168861995).
The spelling of 549111750050 in words is "five hundred forty-nine billion, one hundred eleven million, seven hundred fifty thousand, fifty".
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