Base | Representation |
---|---|
bin | 110011001110100011… |
… | …110011011111001111 |
3 | 12020222101210121001022 |
4 | 303032203303133033 |
5 | 1400122301144413 |
6 | 41134034104355 |
7 | 3655035430661 |
oct | 631643633717 |
9 | 166871717038 |
10 | 55005099983 |
11 | 21366a43819 |
12 | a7b111b0bb |
13 | 5257995a52 |
14 | 293b35c531 |
15 | 166dea7608 |
hex | cce8f37cf |
55005099983 has 2 divisors, whose sum is σ = 55005099984. Its totient is φ = 55005099982.
The previous prime is 55005099893. The next prime is 55005100009. The reversal of 55005099983 is 38999050055.
It is a happy number.
Together with previous prime (55005099893) it forms an Ormiston pair, because they use the same digits, order apart.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 55005099983 - 210 = 55005098959 is a prime.
It is a super-2 number, since 2×550050999832 (a number of 22 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (55005096983) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27502549991 + 27502549992.
It is an arithmetic number, because the mean of its divisors is an integer number (27502549992).
Almost surely, 255005099983 is an apocalyptic number.
55005099983 is a deficient number, since it is larger than the sum of its proper divisors (1).
55005099983 is an equidigital number, since it uses as much as digits as its factorization.
55005099983 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2187000, while the sum is 53.
The spelling of 55005099983 in words is "fifty-five billion, five million, ninety-nine thousand, nine hundred eighty-three".
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