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550069000000 = 2656131719131
BaseRepresentation
bin10000000000100101010…
…10101101011101000000
31221120211020212110001221
420000102222231131000
533003020131000000
61100410451404424
754512136232312
oct10002252553500
91846736773057
10550069000000
111a2312679243
128a734bb3714
133cb432990b0
141c8a2b957b2
15e4965a761a
hex8012aad740

550069000000 has 784 divisors, whose sum is σ = 1650185127360. Its totient is φ = 179712000000.

The previous prime is 550068999839. The next prime is 550069000043. The reversal of 550069000000 is 960055.

It is a happy number.

It is a super-2 number, since 2×5500690000002 (a number of 24 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (25).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 111 ways as a sum of consecutive naturals, for example, 4198999935 + ... + 4199000065.

Almost surely, 2550069000000 is an apocalyptic number.

550069000000 is a gapful number since it is divisible by the number (50) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 550069000000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (825092563680).

550069000000 is an abundant number, since it is smaller than the sum of its proper divisors (1100116127360).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

550069000000 is a wasteful number, since it uses less digits than its factorization.

550069000000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 222 (or 187 counting only the distinct ones).

The product of its (nonzero) digits is 1350, while the sum is 25.

Adding to 550069000000 its reverse (960055), we get a palindrome (550069960055).

The spelling of 550069000000 in words is "five hundred fifty billion, sixty-nine million", and thus it is an aban number.