Base | Representation |
---|---|
bin | 111110100101110011000000… |
… | …1010100100111100000001111 |
3 | 2200012100022100222202101201102 |
4 | 1331023212001110213200033 |
5 | 1034130223111420101221 |
6 | 5230532203452533315 |
7 | 223652052326361641 |
oct | 17513460124474017 |
9 | 2605308328671642 |
10 | 550552552503311 |
11 | 14a472032015976 |
12 | 518b8933a8123b |
13 | 1a827b62a57527 |
14 | 99d4c585b4891 |
15 | 439b206b8330b |
hex | 1f4b98152780f |
550552552503311 has 2 divisors, whose sum is σ = 550552552503312. Its totient is φ = 550552552503310.
The previous prime is 550552552503293. The next prime is 550552552503319. The reversal of 550552552503311 is 113305255255055.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-550552552503311 is a prime.
It is a super-2 number, since 2×5505525525033112 (a number of 30 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (550552552503319) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 275276276251655 + 275276276251656.
It is an arithmetic number, because the mean of its divisors is an integer number (275276276251656).
Almost surely, 2550552552503311 is an apocalyptic number.
550552552503311 is a deficient number, since it is larger than the sum of its proper divisors (1).
550552552503311 is an equidigital number, since it uses as much as digits as its factorization.
550552552503311 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2812500, while the sum is 47.
The spelling of 550552552503311 in words is "five hundred fifty trillion, five hundred fifty-two billion, five hundred fifty-two million, five hundred three thousand, three hundred eleven".
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