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55128214063493 is a prime number
BaseRepresentation
bin11001000100011100010011…
…00111011100100110000101
321020012012120000122122212022
430202032021213130212011
524211210040300012433
6313125315114132525
714416611351635534
oct1442161147344605
9236165500578768
1055128214063493
111662482071619a
126224273421145
13249b750683cac
14d883111a431b
15659028518698
hex3223899dc985

55128214063493 has 2 divisors, whose sum is σ = 55128214063494. Its totient is φ = 55128214063492.

The previous prime is 55128214063399. The next prime is 55128214063523. The reversal of 55128214063493 is 39436041282155.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 48020007544609 + 7108206518884 = 6929647^2 + 2666122^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-55128214063493 is a prime.

It is a super-2 number, since 2×551282140634932 (a number of 28 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (55128214063393) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27564107031746 + 27564107031747.

It is an arithmetic number, because the mean of its divisors is an integer number (27564107031747).

Almost surely, 255128214063493 is an apocalyptic number.

It is an amenable number.

55128214063493 is a deficient number, since it is larger than the sum of its proper divisors (1).

55128214063493 is an equidigital number, since it uses as much as digits as its factorization.

55128214063493 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6220800, while the sum is 53.

The spelling of 55128214063493 in words is "fifty-five trillion, one hundred twenty-eight billion, two hundred fourteen million, sixty-three thousand, four hundred ninety-three".