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55307454131 is a prime number
BaseRepresentation
bin110011100000100101…
…001100011010110011
312021202110201202222002
4303200211030122303
51401232202013011
641224034404215
73665366413646
oct634045143263
9167673652862
1055307454131
1121501685986
12a87643066b
1352a5509227
142969585a5d
15168a7cdc3b
hexce094c6b3

55307454131 has 2 divisors, whose sum is σ = 55307454132. Its totient is φ = 55307454130.

The previous prime is 55307454119. The next prime is 55307454133. The reversal of 55307454131 is 13145470355.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-55307454131 is a prime.

It is a super-2 number, since 2×553074541312 (a number of 22 digits) contains 22 as substring.

Together with 55307454133, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (55307454133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27653727065 + 27653727066.

It is an arithmetic number, because the mean of its divisors is an integer number (27653727066).

Almost surely, 255307454131 is an apocalyptic number.

55307454131 is a deficient number, since it is larger than the sum of its proper divisors (1).

55307454131 is an equidigital number, since it uses as much as digits as its factorization.

55307454131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 126000, while the sum is 38.

The spelling of 55307454131 in words is "fifty-five billion, three hundred seven million, four hundred fifty-four thousand, one hundred thirty-one".