Base | Representation |
---|---|
bin | 10000000110010100101… |
… | …01000110000001010000 |
3 | 1221212202222221210120002 |
4 | 20003022111012001100 |
5 | 33030322441404300 |
6 | 1102040323305132 |
7 | 54651403215332 |
oct | 10031225060120 |
9 | 1855688853502 |
10 | 553150341200 |
11 | 1a3653a46516 |
12 | 8b254b1b1a8 |
13 | 40214790302 |
14 | 1cab60d3452 |
15 | e5c6d675d5 |
hex | 80ca546050 |
553150341200 has 30 divisors (see below), whose sum is σ = 1328943695694. Its totient is φ = 221260136320.
The previous prime is 553150341101. The next prime is 553150341209. The reversal of 553150341200 is 2143051355.
It can be written as a sum of positive squares in 3 ways, for example, as 82872591376 + 470277749824 = 287876^2 + 685768^2 .
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (553150341209) by changing a digit.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 691437527 + ... + 691438326.
Almost surely, 2553150341200 is an apocalyptic number.
553150341200 is a gapful number since it is divisible by the number (50) formed by its first and last digit.
It is an amenable number.
553150341200 is an abundant number, since it is smaller than the sum of its proper divisors (775793354494).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
553150341200 is a wasteful number, since it uses less digits than its factorization.
553150341200 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1382875871 (or 1382875860 counting only the distinct ones).
The product of its (nonzero) digits is 9000, while the sum is 29.
Adding to 553150341200 its reverse (2143051355), we get a palindrome (555293392555).
The spelling of 553150341200 in words is "five hundred fifty-three billion, one hundred fifty million, three hundred forty-one thousand, two hundred".
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