Base | Representation |
---|---|
bin | 110011100010100001… |
… | …011000111000010111 |
3 | 12021211201222211122012 |
4 | 303202201120320113 |
5 | 1401314020323111 |
6 | 41231200254435 |
7 | 3666243222014 |
oct | 634241307027 |
9 | 167751884565 |
10 | 55340011031 |
11 | 21518aa2408 |
12 | a88531141b |
13 | 52ac197c76 |
14 | 296da1c70b |
15 | 168d5b048b |
hex | ce2858e17 |
55340011031 has 2 divisors, whose sum is σ = 55340011032. Its totient is φ = 55340011030.
The previous prime is 55340011019. The next prime is 55340011033. The reversal of 55340011031 is 13011004355.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 55340011031 - 26 = 55340010967 is a prime.
It is a super-2 number, since 2×553400110312 (a number of 22 digits) contains 22 as substring.
Together with 55340011033, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 55340010988 and 55340011006.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (55340011033) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27670005515 + 27670005516.
It is an arithmetic number, because the mean of its divisors is an integer number (27670005516).
Almost surely, 255340011031 is an apocalyptic number.
55340011031 is a deficient number, since it is larger than the sum of its proper divisors (1).
55340011031 is an equidigital number, since it uses as much as digits as its factorization.
55340011031 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 900, while the sum is 23.
Adding to 55340011031 its reverse (13011004355), we get a palindrome (68351015386).
The spelling of 55340011031 in words is "fifty-five billion, three hundred forty million, eleven thousand, thirty-one".
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