Search a number
-
+
55340011033 is a prime number
BaseRepresentation
bin110011100010100001…
…011000111000011001
312021211201222211122021
4303202201120320121
51401314020323113
641231200254441
73666243222016
oct634241307031
9167751884567
1055340011033
1121518aa240a
12a885311421
1352ac197c78
14296da1c70d
15168d5b048d
hexce2858e19

55340011033 has 2 divisors, whose sum is σ = 55340011034. Its totient is φ = 55340011032.

The previous prime is 55340011031. The next prime is 55340011049. The reversal of 55340011033 is 33011004355.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 38552144409 + 16787866624 = 196347^2 + 129568^2 .

It is a cyclic number.

It is not a de Polignac number, because 55340011033 - 21 = 55340011031 is a prime.

It is a super-2 number, since 2×553400110332 (a number of 22 digits) contains 22 as substring.

Together with 55340011031, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 55340010989 and 55340011007.

It is not a weakly prime, because it can be changed into another prime (55340011031) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27670005516 + 27670005517.

It is an arithmetic number, because the mean of its divisors is an integer number (27670005517).

Almost surely, 255340011033 is an apocalyptic number.

It is an amenable number.

55340011033 is a deficient number, since it is larger than the sum of its proper divisors (1).

55340011033 is an equidigital number, since it uses as much as digits as its factorization.

55340011033 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2700, while the sum is 25.

Adding to 55340011033 its reverse (33011004355), we get a palindrome (88351015388).

The spelling of 55340011033 in words is "fifty-five billion, three hundred forty million, eleven thousand, thirty-three".