Base | Representation |
---|---|
bin | 110011100101111101… |
… | …011100011010101001 |
3 | 12021222202112121011201 |
4 | 303211331130122221 |
5 | 1401423302302233 |
6 | 41241020524201 |
7 | 4000543441156 |
oct | 634575343251 |
9 | 167882477151 |
10 | 55397697193 |
11 | 21548612923 |
12 | a8a06b0661 |
13 | 52bb1149a7 |
14 | 297755722d |
15 | 16936a777d |
hex | ce5f5c6a9 |
55397697193 has 2 divisors, whose sum is σ = 55397697194. Its totient is φ = 55397697192.
The previous prime is 55397697191. The next prime is 55397697197. The reversal of 55397697193 is 39179679355.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 49982650624 + 5415046569 = 223568^2 + 73587^2 .
It is a cyclic number.
It is not a de Polignac number, because 55397697193 - 21 = 55397697191 is a prime.
Together with 55397697191, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (55397697191) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27698848596 + 27698848597.
It is an arithmetic number, because the mean of its divisors is an integer number (27698848597).
Almost surely, 255397697193 is an apocalyptic number.
It is an amenable number.
55397697193 is a deficient number, since it is larger than the sum of its proper divisors (1).
55397697193 is an equidigital number, since it uses as much as digits as its factorization.
55397697193 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 48223350, while the sum is 64.
The spelling of 55397697193 in words is "fifty-five billion, three hundred ninety-seven million, six hundred ninety-seven thousand, one hundred ninety-three".
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