554135014634471 has 2 divisors, whose sum is σ = 554135014634472. Its totient is φ = 554135014634470.

The previous prime is 554135014634417. The next prime is 554135014634473. The reversal of 554135014634471 is 174436410531455.

Together with previous prime (554135014634417) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 554135014634471 - 2⁴² = 549736968123367 is a prime.

It is a super-3 number, since 3×554135014634471³ (a number of 45 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

Together with 554135014634473, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (554135014634473) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 277067507317235 + 277067507317236.

It is an arithmetic number, because the mean of its divisors is an integer number (277067507317236).

Almost surely, 2^{554135014634471} is an apocalyptic number.

554135014634471 is a deficient number, since it is larger than the sum of its proper divisors (1).

554135014634471 is an equidigital number, since it uses as much as digits as its factorization.

554135014634471 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12096000, while the sum is 53.

The spelling of 554135014634471 in words is "five hundred fifty-four trillion, one hundred thirty-five billion, fourteen million, six hundred thirty-four thousand, four hundred seventy-one".