Base | Representation |
---|---|
bin | 11001001100110001011010… |
… | …11110111000111011010000 |
3 | 21021012120022222112212201101 |
4 | 30212120231132320323100 |
5 | 24230402223332001300 |
6 | 313505012131114144 |
7 | 14446363155550510 |
oct | 1446305536707320 |
9 | 237176288485641 |
10 | 55414431125200 |
11 | 1672514579a9a4 |
12 | 626b830a42954 |
13 | 24bc734b52bc4 |
14 | d981039b3840 |
15 | 6616cab6db6a |
hex | 32662d7b8ed0 |
55414431125200 has 120 divisors (see below), whose sum is σ = 158767508193408. Its totient is φ = 18173179875840.
The previous prime is 55414431125189. The next prime is 55414431125201. The reversal of 55414431125200 is 252113441455.
It is a self number, because there is not a number n which added to its sum of digits gives 55414431125200.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (55414431125201) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 430171867 + ... + 430300666.
Almost surely, 255414431125200 is an apocalyptic number.
55414431125200 is a gapful number since it is divisible by the number (50) formed by its first and last digit.
It is an amenable number.
55414431125200 is an abundant number, since it is smaller than the sum of its proper divisors (103353077068208).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
55414431125200 is a wasteful number, since it uses less digits than its factorization.
55414431125200 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 860472581 (or 860472570 counting only the distinct ones).
The product of its (nonzero) digits is 96000, while the sum is 37.
Adding to 55414431125200 its reverse (252113441455), we get a palindrome (55666544566655).
The spelling of 55414431125200 in words is "fifty-five trillion, four hundred fourteen billion, four hundred thirty-one million, one hundred twenty-five thousand, two hundred".
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